5c^2-16-16c=0

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Solution for 5c^2-16-16c=0 equation:


Simplifying
5c2 + -16 + -16c = 0

Reorder the terms:
-16 + -16c + 5c2 = 0

Solving
-16 + -16c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-4 + -5c)(4 + -1c) = 0

Subproblem 1

Set the factor '(-4 + -5c)' equal to zero and attempt to solve: Simplifying -4 + -5c = 0 Solving -4 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -5c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -5c = 0 + 4 -5c = 0 + 4 Combine like terms: 0 + 4 = 4 -5c = 4 Divide each side by '-5'. c = -0.8 Simplifying c = -0.8

Subproblem 2

Set the factor '(4 + -1c)' equal to zero and attempt to solve: Simplifying 4 + -1c = 0 Solving 4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1c = 0 + -4 -1c = 0 + -4 Combine like terms: 0 + -4 = -4 -1c = -4 Divide each side by '-1'. c = 4 Simplifying c = 4

Solution

c = {-0.8, 4}

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